How do I check in JavaScript if a value exists at a certain array index?

How do I check in JavaScript if a value exists at a certain array index?

Will this work for testing whether a value at position “index” exists or not, or is there a better way:
// do stuff


Solution 1:

All arrays in JavaScript contain array.length elements, starting with array[0] up until array[array.length - 1]. By definition, an array element with index i is said to be part of the array if i is between 0 and array.length - 1 inclusive.

That is, JavaScript arrays are linear, starting with zero and going to a maximum, and arrays don’t have a mechanism for excluding certain values or ranges from the array. To find out if a value exists at a given position index (where index is 0 or a positive integer), you literally just use

if (index < array.length) {
  // do stuff

However, it is possible for some array values to be null, undefined, NaN, Infinity, 0, or a whole host of different values. For example, if you add array values by increasing the array.length property, any new values will be undefined.

To determine if a given value is something meaningful, or has been defined. That is, not undefined, or null:

if (typeof array[index] !== 'undefined') {


if (typeof array[index] !== 'undefined' && array[index] !== null) {

Interestingly, because of JavaScript’s comparison rules, my last example can be optimised down to this:

if (array[index] != null) {
  // The == and != operators consider null equal to only null or undefined

Solution 2:

Can’t we just do this:

if(arrayName.length > 0){   
    //or **if(arrayName.length)**
    //this array is not empty 
   //this array is empty

Solution 3:

Using only .length is not safe and will cause an error in some browsers. Here is a better solution:

if(array && array.length){   
   // not empty 
} else {
   // empty

or, we can use:


Solution 4:

     // do stuff

Solution 5:

if(arrayName.length > index && arrayName[index] !== null) {
    //arrayName[index] has a value

Solution 6:

Short and universal approach

If you want to check any array if it has falsy values (like false, undefined, null or empty strings) you can just use every() method like this:

array.every(function(element) {return !!element;}); // returns true or false

For example:

['23', null, 2, {key: 'value'}].every(function(element) {return !!element;}); // returns false

['23', '', 2, {key: 'value'}].every(function(element) {return !!element;}); // returns false

['23', true, 2, {key: 'value'}].every(function(element) {return !!element;}); // returns true

If you need to get a first index of falsy value, you can do it like this:

let falsyIndex; 

if(!['23', true, 2, null, {key: 'value'}].every(function(element, index) {falsyIndex = index; return !!element;})) {
} // logs 3

If you just need to check a falsy value of an array for a given index you can just do it like this:

if (!!array[index]) {
  // array[index] is a correct value
else {
  // array[index] is a falsy value