how to compare two string dates in javascript?

how to compare two string dates in javascript?

I have two string dates in the format of m/d/yyyy. For example, “11/1/2012”, “1/2/2013”. I am writing a function in JavaScript to compare two string dates. The signature of my function is
bool isLater(string1, string2), if the date passed by string1 is later than the date passed by string2, it will return true, otherwise false.
So, isLater(“1/2/2013”, “11/1/2012”) should return true. How do I write a JavaScript function for this?

Solutions/Answers:

Solution 1:

var d1 = Date.parse("2012-11-01");
var d2 = Date.parse("2012-11-04");
if (d1 < d2) {
    alert ("Error!");
}

Demo Jsfiddle

Solution 2:

Parse the dates and compare them as you would numbers:

function isLater(str1, str2)
{
    return new Date(str1) > new Date(str2);
}

If you need to support other date format consider a library such as date.js.

Solution 3:

You can simply compare 2 strings

function isLater(dateString1, dateString2) {
  return dateString1 > dateString2
}

Then

isLater("2012-12-01", "2012-11-01")

returns true while

isLater("2012-12-01", "2013-11-01")

returns false

Solution 4:

Directly parsing a date string that is not in yyyy-mm-dd format, like in the accepted answer does not work. The answer by vitran does work but has some JQuery mixed in so I reworked it a bit.

// Takes two strings as input, format is dd-mm-yyyy
// returns true if d1 is smaller than or equal to d2

function compareDates(d1, d2){
var parts =d1.split('/');
var d1 = Number(parts[2] + parts[1] + parts[0]);
parts = d2.split('/');
var d2 = Number(parts[2] + parts[1] + parts[0]);
return d1 <= d2;
}

P.S. would have commented directly to vitran’s post but I don’t have the rep to do that.

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Solution 5:

If your date is not in format standar yyyy-mm-dd (2017-02-06) for example 20/06/2016. You can use this code

var parts ='01/07/2016'.val().split('/');
var d1 = Number(parts[2] + parts[1] + parts[0]);
parts ='20/06/2016'.val().split('/');
var d2 = Number(parts[2] + parts[1] + parts[0]);
return d1 > d2

References