JQuery .each() backwards

JQuery .each() backwards

I’m using JQuery to select some elements on a page and then move them around in the DOM. The problem I’m having is I need to select all the elements in the reverse order that JQuery naturally wants to select them. For example:

  • Item 1
  • Item 2
  • Item 3
  • Item 4
  • Item 5

I want to select all the li items and use the .each() command on them but I want to start with Item 5, then Item 4 etc. Is this possible?


Solution 1:

$($("li").get().reverse()).each(function() { /* ... */ });

Solution 2:

I present you with the cleanest way ever, in the form of the world’s smallest jquery plugin:

jQuery.fn.reverse = [].reverse;


$('jquery-selectors-go-here').reverse().each(function () {
    //business as usual goes here

-All credit to Michael Geary in his post here: http://www.mail-archive.com/discuss@jquery.com/msg04261.html

Solution 3:

You can do

jQuery.fn.reverse = function() {
    return this.pushStack(this.get().reverse(), arguments);

followed by


Solution 4:

Here are different options for this:

First: without jQuery:

var lis = document.querySelectorAll('ul > li');
var contents = [].map.call(lis, function (li) {
    return li.innerHTML;
}).reverse().forEach(function (content, i) {
    lis[i].innerHTML = content;

Demo here

… and with jQuery:

You can use this:

$($("ul > li").get().reverse()).each(function (i) {
    $(this).text( 'Item ' + (++i));

Demo here

Another way, using also jQuery with reverse is:

$.fn.reverse = [].reverse;
$("ul > li").reverse().each(function (i) {
    $(this).text( 'Item ' + (++i));

This demo here.

One more alternative is to use the length (count of elements matching that selector) and go down from there using the index of each iteration. Then you can use this:

var $li = $("ul > li");
$li.each(function (i) {
    $(this).text( 'Item ' + ($li.length - i));

This demo here

One more, kind of related to the one above:

var $li = $("ul > li");
$li.text(function (i) {
    return 'Item ' + ($li.length - i);

Demo here

Solution 5:

I prefer creating a reverse plug-in eg

jQuery.fn.reverse = function(fn) {       
   var i = this.length;

   while(i--) {
       fn.call(this[i], i, this[i])

Usage eg:

$('#product-panel > div').reverse(function(i, e) {

Solution 6:

If you don’t want to save method into jQuery.fn you can use